Trigonometric Equations Question 286
Question: $ \cot \frac{A+B}{2} $ . $ \tan \frac{A-B}{2}= $
[Roorkee 1975]
Options:
A) $ \frac{a+b}{a-b} $
B) $ \frac{a-b}{a+b} $
C) $ \frac{a}{a+b} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
- $ \tan \frac{A-B}{2}=\frac{a-b}{a+b}\cot \frac{C}{2}=\frac{a-b}{a+b}\tan ( \frac{A+B}{2} ) $
Þ $ \tan \frac{A-B}{2}\cot \frac{A+B}{2}=\frac{a-b}{a+b} $ .
BETA
