Trigonometric Equations Question 291
Question: The sides of a triangle are 4, 5 and 6cm. The area of the triangle is equal to
[UPSEAT 2004]
Options:
A) $ \frac{15}{4}cm^{2} $
B) $ \frac{15}{4}\sqrt{7}cm^{2} $
C) $ \frac{4}{15}\sqrt{7}cm^{2} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
- We have, $ a=4cm $ , $ b=5cm $ , $ c=6cm $ Semi-perimeter (s) = $ \frac{a+b+c}{2} $ = $ \frac{4+5+6}{2}=\frac{15}{2} $ cm Area of triangle = $ \sqrt{s,(s-a),(s-b),(s-c)} $ = $ \sqrt{\frac{15}{2},( \frac{15}{2}-4 ),( \frac{15}{2}-5 ),( \frac{15}{2}-6 )}, $ = $ \frac{15}{4}\sqrt{7}cm^{2} $ .
BETA
