Trigonometric Equations Question 306

Question: If the sides of triangle be 6, 10 and 14 then the triangle is

[MP PET 1982]

Options:

A) Obtuse angled

B) Acute angled

C) Right angled

D) Equilateral

Show Answer

Answer:

Correct Answer: A

Solution:

  • $ \cos \theta =\frac{36+100-{{(14)}^{2}}}{2.6.10}\Rightarrow \theta =120^{o} $ .


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