Trigonometric Equations Question 321
Question: If $ A=60^{o} $ , $ a=5,b=4\sqrt{3} $ in $ \Delta ABC $ , then B =
Options:
A) $ 30^{o} $
B) $ 60^{o} $
C) $ 90^{o} $
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
- $ \frac{a}{\sin A}=\frac{b}{\sin B} $
Þ $ \sin B=\frac{(b\sin A)}{a}=\frac{(4\sqrt{3}\sin 60^{o})}{5}=\frac{6}{5}>1 $ , which is inadmissible.
BETA
