Trigonometric Equations Question 332
Question: If $ {{\sec }^{2}}\theta =\frac{4}{3} $ , then the general value of $ \theta $ is
[MP PET 1988]
Options:
A) $ 2n\pi \pm \frac{\pi }{6} $
B) $ n\pi \pm \frac{\pi }{6} $
C) $ 2n\pi \pm \frac{\pi }{3} $
D) $ n\pi \pm \frac{\pi }{3} $
Show Answer
Answer:
Correct Answer: B
Solution:
- $ {{\cos }^{2}}\theta =\frac{3}{4}={{\cos }^{2}}( \frac{\pi }{6} )\Rightarrow \theta =n\pi \pm \frac{\pi }{6} $ .
BETA
