Trigonometric Equations Question 339

Question: If $ 2{{\tan }^{2}}\theta ={{\sec }^{2}}\theta , $ then the general value of $ \theta $ is

[MP PET 1989]

Options:

A) $ n\pi +\frac{\pi }{4} $

B) $ n\pi -\frac{\pi }{4} $

C) $ n\pi \pm \frac{\pi }{4} $

D) $ 2n\pi \pm \frac{\pi }{4} $

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Answer:

Correct Answer: C

Solution:

  • $ 2{{\tan }^{2}}\theta ={{\sec }^{2}}\theta \Rightarrow 2{{\tan }^{2}}\theta ={{\tan }^{2}}\theta +1 $
    $ \Rightarrow $ $ {{\tan }^{2}}\theta =1={{\tan }^{2}}( \frac{\pi }{4} )\Rightarrow \theta =n\pi \pm \frac{\pi }{4} $ .