Trigonometric Equations Question 345

Question: If $ c^{2}=a^{2}+b^{2} $ , then $ 4s(s-a)(s-b)(s-c)= $

[EAMCET 1986; Pb. CET 1990]

Options:

A) $ s^{4} $

B) $ b^{2}c^{2} $

C) $ c^{2}a^{2} $

D) $ a^{2}b^{2} $

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Answer:

Correct Answer: D

Solution:

  • $ \Delta $ is right angled, $ \angle C=90^{o} $
    $ \therefore 4{{\Delta }^{2}}=4{{( \frac{1}{2}ab )}^{2}}=a^{2}b^{2} $ .