Trigonometric Equations Question 366
Question: In a triangle $ ABC $ , if $ b=2,,B=30{}^\circ $ then the area of circumcircle of triangle ABC in square units is
[Karnataka CET 2004]
Options:
A) $ \pi $
B) $ 2\pi $
C) $ 4\pi $
D) $ 6\pi $
Show Answer
Answer:
Correct Answer: C
Solution:
- Radius of circum-circle (R) $ =\frac{a}{2\sin A}=\frac{b}{2\sin B}=\frac{c}{2\sin C} $ $ R=\frac{b}{2\sin B}=\frac{2}{2\sin 30{}^\circ }=2 $ Now, area of circle $ =\pi R^{2}=4\pi $ .
BETA
