Trigonometric Equations Question 384
Question: The general solution of $ \tan 3x=1 $ is
[Karnataka CET 1991]
Options:
A) $ n\pi +\frac{\pi }{4} $
B) $ \frac{n\pi }{3}+\frac{\pi }{12} $
C) $ n\pi $
D) $ n\pi \pm \frac{\pi }{4} $
Show Answer
Answer:
Correct Answer: B
Solution:
- $ \tan 3x=1\Rightarrow \tan 3x=\tan \frac{\pi }{4} $
$ \Rightarrow 3x=n\pi +\frac{\pi }{4} $
$ \Rightarrow $ $ x=\frac{n\pi }{3}+\frac{\pi }{12} $ .
BETA
