SATHEE: Trigonometric-Equations Question 392

Trigonometric-Equations Question 392

Question: The value of $ \theta $ satisfying the given equation $ \cos \theta +\sqrt{3}\sin \theta $ = 2, is

[MNR 1981; EAMCET 1989]

Options:

A) $ \frac{\pi }{3} $

B) $ \frac{5\pi }{3} $

C) $ \frac{2\pi }{3} $

D) $ \frac{4\pi }{3} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ \sin ( \theta +\frac{\pi }{6} )=1=\sin ( \frac{\pi }{2} )\Rightarrow \theta =\frac{\pi }{2}-\frac{\pi }{6}=\frac{\pi }{3} $ .

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Trigonometric-Equations Question 392

Question: The value of $ \theta $ satisfying the given equation $ \cos \theta +\sqrt{3}\sin \theta $ = 2, is

Options:

Answer:

Solution:

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