Trigonometric Equations Question 46

Question: The sides of triangle are $ 3x+4y,\ 4x+3y $ and $ 5x+5y $ units, where $ x,\ y>0. $ The triangle is

[AIEEE 2002]

Options:

A) Right angled

B) Equilateral

C) Obtuse angled

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

  • Let $ a=3x+4y,,b=4x+3y $ and $ c=5x+5y $ . Clearly, c is the largest side and thus the largest angle C is given by $ \cos C=\frac{a^{2}+b^{2}-c^{2}}{2ab}=\frac{-2xy}{2,(12x^{2}+25xy+12y^{2})}<0 $
    $ \Rightarrow $ $ C $ is an obtuse angle. Trick: Check by putting $ x=1, $ $ y=1 $ .