Trigonometric Equations Question 7
Question: General solution of $ \tan 5\theta =\cot 2\theta $ is
[Karnataka CET 2000; Pb. CET 2001]
Options:
A) $ \theta =\frac{n\pi }{7}+\frac{\pi }{14} $
B) $ \theta =\frac{n\pi }{7}+\frac{\pi }{5} $
C) $ \theta =\frac{n\pi }{7}+\frac{\pi }{2} $
D) $ \theta =\frac{n\pi }{7}+\frac{\pi }{3},n\in Z $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \tan 5\theta =\tan ( \frac{\pi }{2}-2\theta ) $
$ \Rightarrow $ $ 5\theta =n\pi +\frac{\pi }{2}-2\theta $
$ \Rightarrow $ $ 7\theta =n\pi +\frac{\pi }{2} $
$ \Rightarrow $ $ \theta =\frac{n\pi }{7}+\frac{\pi }{14} $ .
BETA
