Trigonometric Equations Question 81
Question: The value of $ \theta $ satisfying the given equation $ \cos \theta +\sqrt{3}\sin \theta $ = 2, is
[MNR 1981; EAMCET 1989]
Options:
A) $ \frac{\pi }{3} $
B) $ \frac{5\pi }{3} $
C) $ \frac{2\pi }{3} $
D) $ \frac{4\pi }{3} $
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Answer:
Correct Answer: A
Solution:
- $ \sin ( \theta +\frac{\pi }{6} )=1=\sin ( \frac{\pi }{2} )\Rightarrow \theta =\frac{\pi }{2}-\frac{\pi }{6}=\frac{\pi }{3} $ .