Trigonometric Equations Question 96
Question: If $ 12{{\cot }^{2}}\theta -31,\text{cosec }\theta +32=0 $ , then the value of $ \sin \theta $ is
[Karnataka CET 2005]
Options:
A) $ \frac{3}{5} $ or 1
B) $ -\sin (B+2C)=\frac{1}{2} $ or $ \frac{-2}{3} $
C) $ \frac{4}{5} $ or $ \frac{3}{4} $
D) $ \pm \frac{1}{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
- $ 12{{\cot }^{2}}\theta -31\cos ec\theta +32=0 $ $ 12(cose{c^{2}}\theta -1)-31cos\text{ec }\theta +32=0 $ $ 12cose{c^{2}}\theta -31,cos\text{ec }\theta +20=0 $ $ 12,cose{c^{2}}\theta -16cos\text{ec }\theta -15cosec\theta +20=0 $ $ (4\cos ec\theta -5)(3\cos ec\theta -4)=0 $ $ cosec\theta =\frac{5}{4},\frac{4}{3} $ ; \ $ \sin \theta =\frac{4}{5},\frac{3}{4} $ .
BETA
