Trigonometric Identities Question 102
Question: $ {{(1-\sin A+\cos A)}^{2}} $ is equal to
Options:
A) $ 2(1-\cos A)(1+\sin A) $
B) $ 2(1-sinA)(1+\cos A) $
C) $ 2(1-cos,A)(1-sinA) $
D) None of the above
Show Answer
Answer:
Correct Answer: B
Solution:
$ {{(1-\sin A+\cos A)}^{2}} $ $ =1+{{\sin }^{2}}A+{{\cos }^{2}}A-2\sin A $ $ -2\sin A.\cos A+2\cos A $ $ =2-2\sin A-2\sin A\cos A+2\cos A $ $ =2(1-\sin A)+2\cos A(1-\sin A) $ $ =2(1+\cos A)(1-\sin A) $
BETA
