Trigonometric Identities Question 16
Question: The value of $ \sin 10{}^\circ +\sin 20{}^\circ +\sin 30{}^\circ +…+ $ $ \sin 360{}^\circ $ is
[Pb. CET 2003]
Options:
A) 1
B) 0
C) - 1
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Since $ \sin 190{}^\circ =-\sin 10{}^\circ ,\ \sin 200{}^\circ =-\sin 20{}^\circ , $ $ \sin 210{}^\circ =-\sin 30{}^\circ ,\ \sin 360{}^\circ =\sin 180{}^\circ =0 $ etc.
BETA
