[EAMCET 1981]
A) $ \frac{1}{3} $
B) $ \sqrt{3}-2 $
C) $ 2-\sqrt{3} $
D) None of these
Correct Answer: C
$ \tan 15^{o}=\tan (45^{o}-30^{o}) $ $ =\frac{1-1/\sqrt{3}}{1+1/\sqrt{3}}=\frac{\sqrt{3}-1}{\sqrt{3}+1}\times \frac{\sqrt{3}-1}{\sqrt{3}-1}=2-\sqrt{3} $ .
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