Trigonometric Identities Question 171
Question: If $ p=\frac{2\sin ,\theta }{1+\cos \theta +\sin \theta } $ , and $ q=\frac{\cos \theta }{1+\sin \theta }, $ then
[MP PET 2001]
Options:
A) $ pq=1 $
B) $ \frac{q}{p}=1 $
C) $ q-p=1 $
D) $ q+p=1 $
Show Answer
Answer:
Correct Answer: D
Solution:
$ p=\frac{2,\sin \theta }{1+\cos \theta +\sin \theta },q=\frac{\cos \theta }{1+\sin \theta } $
$ \Rightarrow p+q=\frac{\cos \theta }{1+\sin \theta }+\frac{2,\sin \theta }{1+\sin \theta +\cos \theta },\Rightarrow ,p+q=1. $
BETA
