Trigonometric Identities Question 22
Question: $ \frac{\cos 17{}^\circ +\sin 17{}^\circ }{\cos 17{}^\circ -\sin 17{}^\circ }= $
[MP PET 1998]
Options:
A) $ \tan 62{}^\circ $
B) $ \tan 56{}^\circ $
C) $ \tan 54{}^\circ $
D) $ \tan 73{}^\circ $
Show Answer
Answer:
Correct Answer: A
Solution:
Divided by $ \cos 17^{o} $ in numerator and denominator, we get, $ \frac{\cos 17^{o}+\sin 17^{o}}{\cos 17^{o}-\sin 17^{o}} $ $ =\frac{1+\tan 17^{o}}{1-\tan 17^{o}}=\frac{\tan 45^{o}+\tan 17^{o}}{1-\tan 45^{o}\tan 17^{o}}=\tan 62^{o} $ .
BETA
