Trigonometric Identities Question 225
Question: $ \cos 1{}^\circ .\cos 2{}^\circ .\cos 3{}^\circ ………\cos 179{}^\circ = $
[Karnataka CET 1999; DCE 2005]
Options:
A) 0
B) 1
C) 2
D) $ \frac{1}{2} $
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Answer:
Correct Answer: A
Solution:
We know that one of the factor of the given expression is $ \cos 90{}^\circ =0 $ . Therefore $ \cos 1{}^\circ .\cos 2{}^\circ .\cos 3{}^\circ …\cos 179{}^\circ =0 $ .
BETA
