Trigonometric Identities Question 252
Question: The line $ y=\sqrt{3} $ meets the graph $ y=tanx, $ where $ x\in ( 0,\frac{\pi }{2} ), $ in k points. What is k equal to?
Options:
A) One
B) Two
C) Three
D) Infinity
Show Answer
Answer:
Correct Answer: A
Solution:
Line $ y=\sqrt{3} $ and graph $ =y=\tan x $ Now, we have $ \sqrt{3}=\tan x $
$ \Rightarrow \tan x=\tan 60{}^\circ $
$ \Rightarrow x=60{}^\circ $ $ [ \because x\in ( 0,\frac{\pi }{2} ) ] $ Hence, one intersecting point is possible in the given domain i.e., $ k=1 $ .
BETA
