Trigonometric Identities Question 255
Question: $ \sin 15{}^\circ +\cos 105{}^\circ = $
[MP PET 1992]
Options:
A) 0
B) $ 2\sin 15{}^\circ $
C) $ \cos 15{}^\circ +\sin 15{}^\circ $
D) $ \sin 15{}^\circ -\cos 15{}^\circ $
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Answer:
Correct Answer: A
Solution:
$ \sin 15{}^\circ +\cos 105{}^\circ $ $ \sin 15{}^\circ +\cos (90{}^\circ +15{}^\circ )=\sin 15{}^\circ -\sin 15{}^\circ =0 $ .
BETA
