Trigonometric Identities Question 271

Question: Which pairs of function is identical?

Options:

A) $ f(x)=\sqrt{x^{2}}, $ $ g(x)=x $

B) $ f(x)={{\sin }^{2}}x+{{\cos }^{2}}x;,g(x)=1 $

C) $ f(x)=\frac{x}{x},g(x)=1 $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

For checking equal function Domain of $ f(x)=R $ but range $ =[0,\infty ) $ Domain of $ g(x)=R, $ range =R Domain same but range is different so it is not an equal function. Domain of $ f(x)=R $ Domain of $ g(x)=R $ Domain and range both same so it is an equal function. Domain of $ f(x)=R-{ 0 } $ Domain of $ g(x)=R $ Not equal function as domain is different.