Trigonometric Identities Question 271
Question: Which pairs of function is identical?
Options:
A) $ f(x)=\sqrt{x^{2}}, $ $ g(x)=x $
B) $ f(x)={{\sin }^{2}}x+{{\cos }^{2}}x;,g(x)=1 $
C) $ f(x)=\frac{x}{x},g(x)=1 $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
For checking equal function Domain of $ f(x)=R $ but range $ =[0,\infty ) $ Domain of $ g(x)=R, $ range =R Domain same but range is different so it is not an equal function. Domain of $ f(x)=R $ Domain of $ g(x)=R $ Domain and range both same so it is an equal function. Domain of $ f(x)=R-{ 0 } $ Domain of $ g(x)=R $ Not equal function as domain is different.