Trigonometric Identities Question 299
Question: $ \frac{\sin 2A}{1+\cos 2A}.\frac{\cos A}{1+\cos A}= $
Options:
A) $ \tan \frac{A}{2} $
B) $ \cot \frac{A}{2} $
C) $ \sec \frac{A}{2} $
D) $ cosec\frac{A}{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ ( \frac{\sin 2A}{1+\cos 2A} ),( \frac{\cos A}{1+\cos A} ) $ $ =\frac{2\sin A\cos A}{2{{\cos }^{2}}A}\frac{\cos A}{1+\cos A}=\frac{\sin A}{1+\cos A}=\tan \frac{A}{2} $ .
BETA
