A) $ \tan A $
B) $ \tan 2A $
C) $ \cot A $
D) $ \cot 2A $
Correct Answer: D
$ \frac{1}{\tan 3A-\tan A}-\frac{1}{\cot 3A-\cot A} $ = $ \frac{1}{\tan 3A-\tan A}+\frac{\tan A\tan 3A}{\tan 3A-\tan A}=\frac{1}{\tan 2A}=\cot 2A $ .
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