Trigonometric Identities Question 309
Question: If $ x\sin 45{}^\circ {{\cos }^{2}}60{}^\circ =\frac{{{\tan }^{2}}60{}^\circ cosec30{}^\circ }{\sec 45{}^\circ {{\cot }^{2}}30{}^\circ }, $ then $ x= $
Options:
A) 2
B) 4
C) 8
D) 16
Show Answer
Answer:
Correct Answer: C
Solution:
$ x.\frac{1}{\sqrt{2}}.\frac{1}{4}=\frac{3.2}{\sqrt{2}.3}\Rightarrow \frac{x}{4\sqrt{2}}=\sqrt{2}\Rightarrow x=8 $ .
BETA
