Trigonometric Identities Question 332
Question: If $ \tan ,(A+B)=p,\tan ,(A-B)=q, $ then the value of $ \tan ,2A $ in terms of p and q is
[MP PET 1995, 2002]
Options:
A) $ \frac{p+q}{p-q} $
B) $ \frac{p-q}{1+pq} $
C) $ \frac{p+q}{1-pq} $
D) $ \frac{1+pq}{1-p} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ 2A=(A+B)+(A-B) $
$ \Rightarrow $ $ \tan 2A=\frac{\tan (A+B)+\tan (A-B)}{1-\tan (A+B)\tan (A-B)}=\frac{p+q}{1-pq} $ .
BETA
