Trigonometric Identities Question 350

Question: $ \sin (\pi +\theta )\sin (\pi -\theta ),\text{ cose}{c^{2}}\theta = $

[EAMCET 1980]

Options:

A) 1

B) $ 1 $

C) $ \sin \theta $

D) $ -\sin \theta $

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Answer:

Correct Answer: B

Solution:

$ \sin (\pi +\theta )\sin (\pi -\theta )cose{c^{2}}\theta $ $ =-\sin \theta \sin \theta \frac{1}{{{\sin }^{2}}\theta }=-1 $ .