Trigonometric Identities Question 350
Question: $ \sin (\pi +\theta )\sin (\pi -\theta ),\text{ cose}{c^{2}}\theta = $
[EAMCET 1980]
Options:
A) 1
B) $ 1 $
C) $ \sin \theta $
D) $ -\sin \theta $
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Answer:
Correct Answer: B
Solution:
$ \sin (\pi +\theta )\sin (\pi -\theta )cose{c^{2}}\theta $ $ =-\sin \theta \sin \theta \frac{1}{{{\sin }^{2}}\theta }=-1 $ .