Trigonometric Identities Question 354

Question: $ \sin 50{}^\circ -\sin 70{}^\circ +\sin 10{}^\circ = $

[MNR 1979]

Options:

A) 1

B) 0

C) 1/2

D) 2

Show Answer

Answer:

Correct Answer: B

Solution:

$ \sin 50^{o}-\sin 70^{o}+\sin 10^{o} $ $ =-2\cos 60^{o}\sin 10^{o}+\sin 10^{o} $ $ =,\sin ,10^{o},(1-2\cos 60^{o})=0. $