Trigonometric Identities Question 354
Question: $ \sin 50{}^\circ -\sin 70{}^\circ +\sin 10{}^\circ = $
[MNR 1979]
Options:
A) 1
B) 0
C) 1/2
D) 2
Show Answer
Answer:
Correct Answer: B
Solution:
$ \sin 50^{o}-\sin 70^{o}+\sin 10^{o} $ $ =-2\cos 60^{o}\sin 10^{o}+\sin 10^{o} $ $ =,\sin ,10^{o},(1-2\cos 60^{o})=0. $