[MNR 1979]
A) $ \frac{2-\sqrt{3}}{2} $
B) $ \frac{\sqrt{3}+1}{2\sqrt{2}} $
C) $ \frac{\sqrt{3}-1}{-2\sqrt{2}} $
D) $ \frac{\sqrt{3}-1}{2\sqrt{2}} $
Correct Answer: B
$ \sin ,75^{o}=\sin (90^{o}-15^{o})=\cos ,15^{o}=\cos (45^{o}-30^{o}) $ $ =\frac{\sqrt{3}+1}{2\sqrt{2}} $ .
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