Trigonometric-Identities Question 390
Question: The expression $ \frac{\cos 6x+6\cos 4x+15\cos 2x+10}{\cos 5x+5\cos 3x+10\cos x} $ is equal to
Options:
A) $ \cos 2x $
B) $ 2\cos x $
C) $ {{\cos }^{2}}x $
D) $ 1+\cos x $
Show Answer
Answer:
Correct Answer: B
Solution:
The given expression can be written as $ \frac{(\cos ,6x+\cos ,4x)+5,(\cos ,4x+\cos ,2x)+10,(\cos ,2x+1)}{\cos ,5x+5,\cos ,3x+10,\cos x} $ After solving, we get the required result i.e. $ 2,\cos x $ .
BETA
