Trigonometric Identities Question 5
Question: $ \tan A+\cot (180{}^\circ +A)+\cot (90{}^\circ +A)+\cot (360{}^\circ -A) $
[MP PET 1992]
Options:
A) 0
B) $ 2\tan A $
C) $ 2\cot A $
D) $ 2(\tan A-\cot A) $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \tan A+\cot (180{}^\circ +A)+\cot (90{}^\circ +A)+\cot (360{}^\circ -A) $ $ =\tan A+\cot A-\tan A-\cot A=0 $ .
BETA
