Trigonometric Identities Question 67
Question: $ \sin 163^{o}\cos 347^{o}+\sin 73^{o}\sin 167^{o}= $
[MP PET 2000]
Options:
A) 0
B) 1/2
C) 1
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ \sin 163^{o}\cos 347^{o}+\sin 73^{o}\sin 167^{o} $ $ =\sin (180^{o}-17^{o})\cos (360^{o}-13^{o})+\cos (90^{o}-17^{o}) $ $ \sin (180^{o}-13^{o}) $ $ =\sin 17^{o}\cos 13^{o}+\cos 17^{o}\sin 13^{o}=\sin 30^{o}=1/2 $ .
BETA
