Trigonometric Identities Question 69
Question: The value of $ \sin 600{}^\circ \cos 330{}^\circ +\cos 120{}^\circ \sin 150{}^\circ $ is
[MP PET 1994]
Options:
A) -1
B) 1
C) $ \frac{1}{\sqrt{2}} $
D) $ \frac{\sqrt{3}}{2} $
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Answer:
Correct Answer: A
Solution:
$ \sin ,600^{o},\cos ,330^{o}+\cos ,120^{o},\sin ,150^{o} $ $ =-\sin ,60^{o},\cos ,30^{o}-\sin ,30^{o},\cos ,60^{o} $ $ =-{ \sin ,(60^{o}+30^{o}) }=-1 $ .
BETA
