Trigonometric Identities Question 78
Question: If $ A+C=B, $ then $ \tan A\tan B\tan C= $
[EAMCET 1986]
Options:
A) $ \tan A\tan B+\tan C $
B) $ \tan B-\tan C-\tan A $
C) $ \tan A+\tan C-\tan B $
D) $ -(\tan A\tan B+\tan C) $
Show Answer
Answer:
Correct Answer: B
Solution:
$ B=A+C\Rightarrow \tan B=\tan (A+C) $
$ \tan B=\frac{\tan A+\tan C}{1-\tan A\tan C} $
$ \tan A\tan B\tan C=\tan B-\tan A-\tan C $ .
BETA
