Trigonometric Identities Question 79
Question: If $ A=130{}^\circ $ and $ x=\sin A+\cos A, $ then
[CET 1989]
Options:
A) $ x>0 $
B) $ x<0 $
C) $ x=0 $
D) $ x\le 0 $
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Answer:
Correct Answer: A
Solution:
$ x=\cos 40{}^\circ +\cos 130{}^\circ =2\cos 85{}^\circ \cos 45{}^\circ >0 $ .