Trigonometric Identities Question 79

Question: If $ A=130{}^\circ $ and $ x=\sin A+\cos A, $ then

[CET 1989]

Options:

A) $ x>0 $

B) $ x<0 $

C) $ x=0 $

D) $ x\le 0 $

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Answer:

Correct Answer: A

Solution:

$ x=\cos 40{}^\circ +\cos 130{}^\circ =2\cos 85{}^\circ \cos 45{}^\circ >0 $ .