Vector Algebra Question 183
Question: In a regular hexagon ABCDEF, $ \overrightarrow{AE}= $
[MNR 1984]
Options:
A) $ 2\mathbf{a}-3\mathbf{b} $
B) $ \overrightarrow{AC}+\overrightarrow{AF}-,\overrightarrow{AB} $
C) $ \overrightarrow{AC}+\overrightarrow{AB}-\overrightarrow{AF} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
- Obviously, $ \overrightarrow{AE}=\overrightarrow{AC}+\overrightarrow{CD}+\overrightarrow{DE} $ $ =\overrightarrow{AC}+\overrightarrow{AF}-\overrightarrow{AB} $ , $ { ,\because \overrightarrow{CD}=\overrightarrow{AF},and,\overrightarrow{DE}=-\overrightarrow{AB} } $ .
BETA
