Vector Algebra Question 242
Question: If the position vectors of the points A, B, C, D be $ 2\mathbf{i}+3\mathbf{j}+5\mathbf{k}, $ $ \mathbf{i}+2\mathbf{j}+3\mathbf{k},-5\mathbf{i}+4\mathbf{j}-2\mathbf{k} $ and $ \mathbf{i}+10\mathbf{j}+10\mathbf{k} $ respectively, then
[MNR 1982]
Options:
A) $ \overrightarrow{AB}=\overrightarrow{CD} $
B) $ \overrightarrow{AB},||,\overrightarrow{,CD} $
C) $ \overrightarrow{AB}\bot \overrightarrow{CD} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
- $ \overrightarrow{AB}=-\mathbf{i}-\mathbf{j}-2\mathbf{k} $ and $ \overrightarrow{CD}=6\mathbf{i}+6\mathbf{j}+12\mathbf{k} $ Hence, $ \overrightarrow{AB}||\overrightarrow{CD}. $
BETA
