Vector Algebra Question 256
Question: In the triangle ABC, $ \overrightarrow{AB}=\mathbf{a},\overrightarrow{AC}=\mathbf{c},\overrightarrow{BC}=\mathbf{b} $ , then
[RPET 1984]
Options:
A) $ \mathbf{a}+\mathbf{b}+\mathbf{c}=\mathbf{0} $
B) $ \mathbf{a}+\mathbf{b}-\mathbf{c}=\mathbf{0} $
C) $ \mathbf{a}-\mathbf{b}+\mathbf{c}=\mathbf{0} $
D) $ -,\mathbf{a}+\mathbf{b}+\mathbf{c}=\mathbf{0} $
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Answer:
Correct Answer: B
Solution:
- $ \overrightarrow{AB}+\overrightarrow{BC}+\overrightarrow{CA}=0\Rightarrow \mathbf{a}+\mathbf{b}-\mathbf{c}=0. $
BETA
