Vector Algebra Question 265
Question: The position vector of the points which divides internally in the ratio 2 : 3 the join of the points $ 2\mathbf{a}-3\mathbf{b} $ and $ 3\mathbf{a}-2\mathbf{b}, $ is
[AI CBSE 1985]
Options:
A) $ \frac{12}{5}\mathbf{a}+\frac{13}{5}\mathbf{b} $
B) $ \frac{12}{5}\mathbf{a}-\frac{13}{5}\mathbf{b} $
C) $ \frac{3}{5}\mathbf{a}-\frac{2}{5}\mathbf{b} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
- Position vectors of the points which divides internally is, $ \frac{3(2\mathbf{a}-3\mathbf{b})+2(3\mathbf{a}-2\mathbf{b})}{5}=\frac{12\mathbf{a}-13\mathbf{b}}{5}. $
BETA
