Vector Algebra Question 289
Question: If O be the origin and the position vector of A be $ 4,\mathbf{i}+5,\mathbf{j}, $ then a unit vector parallel to $ \overrightarrow{OA} $ is
Options:
A) $ \frac{4}{\sqrt{41}}\mathbf{i} $
B) $ \frac{5}{\sqrt{41}}\mathbf{i} $
C) $ \frac{1}{\sqrt{41}}(4,\mathbf{i}+5,\mathbf{j}) $
D) $ \frac{1}{\sqrt{41}}(4,\mathbf{i}-5,\mathbf{j}) $
Show Answer
Answer:
Correct Answer: C
Solution:
- Unit vector prarallel to $ \overrightarrow{OA} $ $ =\frac{4\mathbf{i}+5\mathbf{j}}{\sqrt{16+25}}=\frac{1}{\sqrt{41}}(4\mathbf{i}+5\mathbf{j}). $
BETA
