Vector Algebra Question 375

Question: If a and b are two unit vectors such that $ \mathbf{a}+2,\mathbf{b} $ and $ 5a-4b $ are perpendicular to each other, then the angle between a and b is

[IIT Screening 2002]

Options:

A) $ 45^{o} $

B) $ 60^{o} $

C) $ {{\cos }^{-1}}( \frac{1}{3} ) $

D) $ {{\cos }^{-1}}( \frac{2}{7} ) $

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Answer:

Correct Answer: B

Solution:

  • $ (\mathbf{a}+2\mathbf{b}),.,(5\mathbf{a}-4\mathbf{b})=0 $ or $ 5{{\mathbf{a}}^{2}}+6\mathbf{a},.,\mathbf{b}-8{{\mathbf{b}}^{2}}=0 $ or $ 6,\mathbf{a},.,\mathbf{b}=3, $ $ (\because {{\mathbf{a}}^{2}}=1,,{{\mathbf{b}}^{2}}=1) $
    $ \therefore ,\mathbf{a},.,\mathbf{b}=\frac{1}{2} $ or $ |\mathbf{a}||\mathbf{b}|\cos \theta =\frac{1}{2} $
    $ \therefore ,\cos \theta =\frac{1}{2},,,\therefore \theta =60^{o}. $