Vector Algebra Question 41
Question: The perimeter of a triangle with sides $ 3\mathbf{i}+4\mathbf{j}+5\mathbf{k},, $ $ 4\mathbf{i}-3\mathbf{j}-5\mathbf{k} $ and $ 7\mathbf{i}+\mathbf{j} $ is
[MP PET 1991]
Options:
A) $ \sqrt{450} $
B) $ \sqrt{150} $
C) $ \sqrt{50} $
D) $ \sqrt{200} $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ l_1=\sqrt{25+25}=5\sqrt{2}, $ $ l_2=\sqrt{25+25}=5\sqrt{2} $ , $ l_3=5\sqrt{2}. $ Hence, $ l_1+l_2+l_3=3\sqrt{50}=\sqrt{450}. $
BETA
