Atoms And Nuclei Question 100
Question: The radius of the Bohr orbit in the ground state of hydrogen atom is 0.5 Å. The radius of the orbit of the electron in the third excited state of $ H{{e}^{+}} $ will be [MP PMT 2000]
Options:
A) 8 Å
B) 4 Å
C) 0.5 Å
D) 0.25 Å
Show Answer
Answer:
Correct Answer: B
Solution:
By using $ r_{n}=r_{0}\frac{n^{2}}{Z} $ ;
Where r0 = Radius of the Bohr orbit in the ground state atom .
So for $ H{{e}^{+}} $ third excited state $ n=4,\ Z=2,\ r_{0}=0.5{\AA} $ Þ $ r_{4}=0.5\times \frac{4^{2}}{2}=4{\AA} $
BETA
