A) 13.6 eV
B) 27.2 eV
C) 54.4 eV
D) 100 eV
Correct Answer: C
For the ionization of second He electron. $ H{{e}^{+}} $ will act as hydrogen like atom. Hence ionization potential $ =Z^{2}\times 13.6,volt={{(2)}^{2}}\times 13.6=54.4,V $
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