Atoms And Nuclei Question 420
Energy of an electron in an excited hydrogen atom is - 3.4 eV. Its angular momentum will be: $ L = \frac{nh}{2\pi} $, where $ n = 2 $ and $ h=6.626\times {{10}^{-34}}J-s $
Options:
A) $ 1.11\times 10^{-34}J\ \sec $
B) $ 1.51\times {{10}^{-31}}J\ \sec $
C) $ 2.11\times {{10}^{-34}}J\ \sec $
D) $ 3.72\times {{10}^{-34}}J\ \sec $
Show Answer
Answer:
Correct Answer: C
Solution:
- The electron is in the second orbit (n=2) Hence $ \hbar =2.11\times {{10}^{-34}}J\text{-}sec $
BETA
