Atoms And Nuclei Question 441
Question: The velocity of an electron in the second orbit of sodium atom (atomic number = 11) is v. The velocity of an electron in its fifth orbit will be
Options:
A) v
B) $ \frac{22}{5}v $
C) $ \frac{5}{2}v $
D) $ \frac{2}{5}v $
Show Answer
Answer:
Correct Answer: D
Solution:
- vn $ \propto \frac{1}{n} $
Þ $ \frac{v_{5}}{v_{2}}=\frac{2}{5}\Rightarrow v_{5}=\frac{2}{5}v_{2}=\frac{2}{5}v $
BETA
