Atoms And Nuclei Question 50
Question: Ratio of the wavelengths of first line of Lyman series and first line of Balmer series is [EAMCET (Engg.) 1995; MP PMT 1997]
Options:
A) 1: 3
B) 27 : 5
C) 5 : 27
D) 4 : 9
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{1}{\lambda }=R( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} ) $
For first line of Lymen series n1 = 1 and n2 = 2
For first line of Balmer series n2 = 2 and n2 = 3
So, $ \frac{{\lambda_{Lymen}}}{{\lambda_{Balmer}}}=\frac{5}{27} $
BETA
