Atoms And Nuclei Question 53
Question: According to Bohr’s theory the moment of momentum of an electron revolving in second orbit of hydrogen atom will be [MP PET 1999; KCET 2003]
Options:
A) $ 2\pi h $
B) $ \pi h $
C) $ \frac{h}{\pi } $
D) $ \frac{2h}{\pi } $
Show Answer
Answer:
Correct Answer: C
Solution:
Angular momentum $ L=n( \frac{h}{2\pi } ) $ For this case n=2, hence $ L=2\times \frac{h}{2\pi }=\frac{h}{\pi } $
BETA
