Atoms And Nuclei Question 289
Question: An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The energy (in eV) required to remove both the electrons from a neutral helium atom is
Options:
A) 38.2
B) 49.2
C) 51.8
D) 79.0
Show Answer
Answer:
Correct Answer: D
Solution:
- For helium ion, Z=2 and for first orbit n=1
$ \therefore E_{1}=\frac{-13.6}{{{( 1 )}^{2}}}\times 2^{2}=-54.4eV $
$ \therefore $ Energy required to remove this $ {{e}^{-}}=+54.4eV $
$ \therefore $ Total energy required $ =54.4+24.6=79eV $
BETA
